s0669
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include/s0669_trim_a_binary_search_tree.hpp
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include/s0669_trim_a_binary_search_tree.hpp
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#ifndef S0669_TRIM_A_BINARY_SEARCH_TREE_HPP
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#define S0669_TRIM_A_BINARY_SEARCH_TREE_HPP
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#include "structures.hpp"
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class S0669 {
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public:
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TreeNode* trimBST(TreeNode* root, int low, int high);
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};
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#endif
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- [s0235](https://leetcode.cn/problems/lowest-common-ancestor-of-a-binary-search-tree/description/): 找两个指定节点的最近公共祖先。思路很简单,只要出现分岔(即一个在当前节点的左边,一个在当前节点的右边),那么这个分岔点就是最近公共祖先。
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- [s0701](https://leetcode.cn/problems/insert-into-a-binary-search-tree/description/): 插入节点。一层一层往下找,直到发现找不到了就在这个地方插入。
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- [s0450](https://leetcode.cn/problems/delete-node-in-a-bst/description/): 删除节点。递归删除。
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- [s0669](https://leetcode.cn/problems/trim-a-binary-search-tree/description/): 修剪 BST 。递归修剪。
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src/s0669_trim_a_binary_search_tree.cpp
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src/s0669_trim_a_binary_search_tree.cpp
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#include "s0669_trim_a_binary_search_tree.hpp"
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TreeNode* S0669::trimBST(TreeNode* root, int low, int high) {
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if (root == nullptr) return nullptr;
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if (low <= root->val && root->val <= high) {
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// 如果根节点的值位于范围内,则对左右子树进行剪裁
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root->left = trimBST(root->left, low, high);
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root->right = trimBST(root->right, low, high);
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return root;
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} else if (root->val < low) {
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// 如果根节点的值小于 low, 把根节点和左子树都剪裁掉
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return trimBST(root->right, low, high);
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} else {
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// 如果根节点的值大于 high, 把根节点和右子树都剪裁掉
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return trimBST(root->left, low, high);
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}
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}
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